1.

In triangle ABC right angled at C, the valueof Cos (A+B) is​

Answer»

We know that the sum of all 3 angles in a triangle is 180° .C=90° But,A+B+C=180° ⟹A+B=(180−90)°=90° We ALSO know that cos90°=0 HENCE,COS(A+B)=0this is the correct solution



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