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in triangle ABC ~ triangle PQR, area of triangle ABC is 80 and area of triangle PQR is 125 find AB/PQ |
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Answer» GivenΔABC∼ΔPQRA(ΔABC)=80A(ΔPQR)=125 According to theorem of areas of SIMILAR TRIANGLES ""When two triangles are similar, the ratio of areas of those triangles is EQUAL to the ratio of the square of their corresponding sides'∴ A(ΔPQR)A(ΔABC) = PQ 2 AB 2 ⇒ 12580 = PQ 2 AB 2 2516 = PQ 2 AB 2 ⇒ 5 2 4 2 = PQ 2 AB 2 ⇒ PQAB = 54 Therefore,A(ΔPQR)A(ΔABC) = 12580 and PQAB = 54 |
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