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In triangle OPQ where m angle P = 90° . If OP = 7 cms. and OQ - PQ = 1 cms. Find the values of sin Q and cos Q. |
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Answer» triangle OPQ m ∠P = 90° OP = 7 cm and OQ - PQ = 1 cm To Find : values of SIN Q and cos Q. Solution:m ∠P = 90° => ΔOPQ is right angled at PLet SAY PQ = xOQ - PQ = 1=> OQ - x = 1=> OQ = x + 1OP = 7OQ² = OP² + PQ²=> (x + 1)² = 7² + x²=> x² + 2x + 1 = 49 + x²=> 2x = 48=> x = 24PQ = 24OQ = 25Sin Q = OP/OQ=> Sin Q = 7/25Cos Q = PQ/OQ=> Cos Q = 24/25Learn More:∆ XYZ is a right angled triangle, right angle at Y . YZ=b and a= A ...brainly.in/question/15114979 In triangle ABC, seg DE || SEG BC. if twice area of triangle ADE ... brainly.in/question/4599623 in triangle pqr, if qs is the angle bisector of angle q then show that A ... brainly.in/question/12931931 |
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