In triangleAOB and triangleCOD, B=C and O is the midpoint of BC. Find the values of x and y ifAB = 3x units, CD = y + 2 units, AO = x + 2units, DO = y units.

In triangleAOB and triangleCOD, B=C and O is the midpoint of BC. Fin

1.	In triangleAOB and triangleCOD, B=C and O is the midpoint of BC. Find the values of x and y ifAB = 3x units, CD = y + 2 units, AO = x + 2units, DO = y units.
Answer» Step-by-step EXPLANATION:N ∆AOB and ∆COD, ⟨B = ⟨C . And O is the midpoint of BC . BO = CO Let, ACCORDING to the question AB = 3x units CD = y + 2 units AO = x + 2 units DO = y unitsTO FINDThe VALUE of x and y .SOLUTION 3x - y - (x - y) = 2 - (-2) => 3x - y - x + y = 2 + 2 => 2X = 4 => x = 4/2 X=2⚡ Put the value of “ x = 2 ” in equation (2), we get => 2 - y = -2. => y = 2 + 2Y=4The value of “x” is 2 and the value of “y” is 4 .

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In triangleAOB and triangleCOD, B=C and O is the midpoint of BC. Find the values of x and y ifAB = 3x units, CD = y + 2 units, AO = x + 2units, DO = y units.​

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In triangleAOB and triangleCOD, B=C and O is the midpoint of BC. Find the values of x and y ifAB = 3x units, CD = y + 2 units, AO = x + 2units, DO = y units.