1.

In two different experiment X-rays are incident on sodium metal and then X-rays are incident on copper.In both case stoppin potential V_(0) is measured ,stopping potential …given [(phi_(0))_(na)lt(phi_(0))_(cu)]

Answer»

will be same in both case
will be more for SODIUM metal
more for copper
will be infinite for both metal

Solution :`eV_(0)=hf-phi`
`phi_(NA)ltphi_(cu)`
`therefore V_(0NA)gtV_(0CU)`


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