In two separate collisions, the coefficient of restitutions `e_(1)` and `e_(2)` are in the ratio `3 : 1`. In the first collision the relative velocity of approach is twice the relative velocity of separation. Then, the ratio between relativevelocity of approach and relative velocity of separation in the second collision isA. `1 :6`B. `2 : 3`C. `3 : 2`D. `6 : 1`

In two separate collisions, the coefficient of restitutions `e_(1)` an

1.	In two separate collisions, the coefficient of restitutions `e_(1)` and `e_(2)` are in the ratio `3 : 1`. In the first collision the relative velocity of approach is twice the relative velocity of separation. Then, the ratio between relativevelocity of approach and relative velocity of separation in the second collision isA. `1 :6`B. `2 : 3`C. `3 : 2`D. `6 : 1`
Answer» Correct Answer - D `e_(1):e_(2) = 3:1 , Delta U_(1) = 2Delta V_(1) rArr e_(1) = (Delta V_(1))/(Delta U_(1)) =(1)/(2)` `(Delta V_(1))/(Delta U_(1)) :(Delta V_(2))/(Delta U_(2)) =3:1`.

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