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In two similar △ABC & PQR , the corresponding medians AD & PS are in the ratio 2 : 3. If the area of △ABC is 20 sq cm , then what is the area of △PQR? |
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Answer» ANSWERSince the areas of TWO SIMILAR TRIANGLES are in the ratio of the squares of the CORRESPONDING altitudes.∴ AREA(△PQR)Area(△ABC) = PS 2 AD 2 ⇒ Area(△PQR)Area(△ABC) =( 94 ) 2 = 8116 [∵AD:PS=4:9]⇒ Area(△PQR)Area(△ABC) = 8116 |
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