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In what are the charger on all the four capacitors? . |
Answer» Solution :Let us assign the potentials at nodes `N_(1)` and `N_(2)` as `x` and `y`, respectively. We have identified two isolated systems in the circuits asmarked in The potentials at defferent junctions are marked ACCORDING to the emf of the BATTERIES as shown in the figure. The charge APPEARING in each CAPACITORS is marded as per the formula `q=CDeltaV`  In the isolated systems `(1)` and `(2)` the net should to CONSERVED. For the isolated system `(1)`, `2(x-10)+4(x-y)+2x=0` or `8x-4y-20=0` or `2x-y=5`  . For the isolated system `(2)` `-4(x-y)+4(y-15)+4(y-5)=0` or `-4x+12y-80` or `-2x+6y=40` Adding Eqs. `(i)` and `(ii)`, we get `5y=45` or `y=9 V` and `x=7 V` Hence, the charges on different capacitors are shown in. |
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