1.

In what ratio by mass, sulphur trioxide and nitrogen should be mixed so that the partial pressure exerted by each gas is same ?

Answer»

`7:20`
7 `:` 40
20 `:` 7
40 `:` 7

Solution :Partial pressure of a gas = MOLE FRACTION TOTAL pressure
For partial pressure to be EQUAL,
`x ( SO_(3)) = x ( N_(2))`
`x ( SO_(3)) = ( W_(1) // 80)/( W_(1) // 80 + W_(2) // 28)`
and `x(N_(2)) = ( W_(2)// 28) / ((W_(1))/( 80) + ( W_(2))/( 28))`
`( W_(1))/( 80) = ( W_(2))/( 28)`
`( W_(1))/( W_(2)) = ( 80)/( 28) = ( 20)/( 7)`


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