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in what time will the compound interest on ₹5120 at 12half 1/2% per annum compounded annually be ₹1360 |
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Answer» For solving and finding the cos-1x ,we have to remember below THREE listed formulae.limh->0 {f(x + H) – f(x)} / hcos-1x + sin-1x = pi/2cos-1x = pi/2 – sin-1xNow, LET’s solve, we have.f(x) = cos-1xf(x + h) = cos-1(x + h)limh->0 {cos-1(x + h ) – cos-1(x)} / hlimh->0 {pi/2 – sin-1(x + h) – (pi/2 – sin-1x) } / hlimh->0 {pi/2 – sin-1(x + h) – pi/2 + sin-1x } / hTaking – SIGN common, we GET– limh->0 {sin-1(x + h) – sin-1x} / hSince we know that limh->0 { sin-1(x + h) – sin-1x } / h = 1 / √(1 – x2)Putting the value in our solution we get,– 1 / √(1 – x2) |
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