1.

In Wheatstone's network P = 2 Omega , Q = 2 Omega , R = 2 Omegaand S = 3 OmegaThe resistance with which S is to shunted in order that the bridge may be balanced is

Answer»

`6Omega`
`4Omega`
`2Omega`
`1OMEGA`

Solution :`(P)/(Q)= (R )/(S^(1))`
`(2)/(2) = (2)/((3 xx x)/(3 + x)) rArr (3X)/(3+ x)=2 rArr 3x = 6+ 2x rArr x= 6 Omega`


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