1.

In Which case (s), there is change in oxidation number ?

Answer»

AQUEOUS solution of `CrO_(4)^(2-)` is acidified
`SO_(2)` gas is passed through acidified `Cr_(2)O_(7)^(2-)` solution
`Cr_(2)O_(7)^(2-)` solution is MADE alkaline
`CrO_(2)Cl_(2)` is is dissolved in NaOH.

Solution :(a) `2overset(+6)(CR)O_(4)^(2-)+2H^(+)rarroverset(+6)Cr_(2)O_(7)^(2-)+H_(2)O " "("no change")`
`overset(+6)Cr_(2)O_(4)^(2-)+3overset(+4)SO_(2)+2H^(+)rarr2overset(+3)Cr^(3+)+3overset(+6)SO_(4)^(2-)+H_(2)O" "("change")`
`overset(+6)Cr_(2)O_(7)^(2-)+2OH^(-)rarr2overset(+6)CrO_(4)^(2-)+H_(2)O" "("no change")`
`overset(+6)CrO_(2)Cl_(2)+2NaOHrarrNaoverset(+6)CrO_(4)+2HCl" "("no change")`.


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