1.

In which of the following compounds , nitrogen exhibits highest oxidation state ?

Answer»

`N_(2)H_(4)`
`NH_(3)`
`N_(3)H`
`NH_(2)OH`

Solution :`N_(2)H_(4)rArr2x+4(+1)or2x+4=0`
`therefore""x=-2`
`NH_(3)rArrx+3(+1)=0orx+3=0`
`therefore""x=-3`
`N_(3)HrArr3x+1(+1)=0or3x+1=0`
`therefore"" x=-1//3`
`NH_(2)OHrArrx+2+(-2)+1=0orx+1=0`
`therefore "" x=-1`
THUS , highest oxidation STATE is `-1//3`.


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