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in which quadrant the points which divide the line segment joining the points (5,4) and (-6,-7) in the ratio 1:3 internally lies? |
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Answer» We know if a point divides the line segment AB joining two points in given ratio m:n internally, then by SECTION FORMULA, the co-ordinates of a point are given as =( m+n mx 2 +nx 1 , m+n my 2 +ny 1 ) Hence, the ratio is m:n=2:1 and A(X 1 ,y 1 ) = (3,4) and B(x 2 ,y 2 ) = (7,−6) ∴ Point =( m+n mx 2 +nx 1 , m+n my 2 +ny 1 ) =( 2+1 2×7+1×3 , 2+1 2×−6+1×4 ) =( 3 17 , 3 −8 ) ∴ The point lies in IV quadrant.Step-by-step explanation: |
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