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In YDSE arangement shown in figure, fringes are seen on screen using monochromatic source S having wavelength 3000 overset(@)Delta (in air). S_(1) and S_(2) are two slits separate by d = 1mm and D = 1m . Left of slits S_(1) and S_(2) medium of refractive index mu_(1) = 2 is presernt refractive index mu_(2) = (3)/(2) is present. A thin slab of thickness 't' is placed in front of S_(1) . The refractive index of slab mu_(3) varies with distance from its starting face as shown in figure. If the thickness of the slab is selected 1mu m , then the position of the central maxima will be (y - coordinate) |
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Answer» `(1)/(3)mm`  AREA `(A) = mu_(3) (dx) = ((1+3)t)/(2) = 2T` From the above equation `O = 1XX10^(-6) + (3)/(2) (yd)/(D) -0.5t(3)/(2)xx(yd)/(D) = 0.5t-1xx10^(-6)` `= 0.5xx10^(-6)-1xx10^(-6) = -0.5xx10^(-6)` `y = -(10^(-6))/(2)xx(2)/(3)xx(D)/(d) = (-10^(-6)XX1)/(3xx1xx10^(-3)) = -(1)/(3)xx10^(-3)` `y= -(1)/(3)mm` |
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