1.

In YDSE,D=1m, d=4mm and lamda=1/2mm in the figure shown, a parallel beam of light is incident on the plane of the slits of YDSE. Light incident on the slit s_(1), passes through a medium of variable refractive index mu=(2x+1) (where x is the distance from the plane of slits in mm) up to a distance l=1mm before falling on s_(1). Rest of the space filled with air. Then choose the correct option (s):

Answer»

Position of central brigh FRINGE is at a DISTANC `y=1/(sqrt(3))m` above the central line
Position of central bright fringe is at a distance `y=1/2m` above the central line
Number of maxima obtaining on the SCREENING is 7
Number of maxima obtaining on the screening is 8

Solution :For central height fringe
`dsintheta=2mm`
`4mmsintheta=2mm`
`theta=30^(@)`
`TAN30^(@)=y/2`
For bright fringe (`dsin theta+-2)=nlamda`
where `n` is `0,1,2,3,……….`


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