1.

In YDSE the distance between the slits is 1mm and screen is 25nm away from intensities IF the wavelength of light is 6000A the fringe width on the screen is

Answer»

0.15MM
0.30mm
0.24mm
0.12 mm

Solution :`BETA=(lamdaD)/d=(6000 TIMES 10^-10 times 0.25)/(1 times 10^-3)m=0. 15mm`


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