1.

In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m from the screen. The wavelenght of light used is 5000A^(0). Find the distance between 7th maxima 11th minima on the screen.

Answer»

SOLUTION :Given, `d= 0.1 mm, D= 0.5 m` and `LAMBDA= 5000 dotA= 5.0xx10^(-7)m`
`triangle y= (y_(11))_("dark")-(y_(7))_("bright")= ((2xx11 -1)lambda D)/(2D)-(7 lambda D)/(d)`
`= 8.75xx 10^(-3) m = 8.75 mm`


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