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In YDSE, the two slits are separated by 0.1 mm and they are 0.5m from the screen. The wavelength of light used is 5000 Å. Find the distance between 7th maxima and 11th minima on the screen. |
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Answer» SOLUTION :GIVEN, d= 0.1mm, D=0.5m and `lamda = 5000Å = 5.0 xx 10^(-7) m` `Delta y = (y_11)_(dark) - (y_7)_("BRIGHT") =((2 xx 11 - 1)lamda D )/(2d) - (7 lamda D)/(d)` `= 8.75 xx 10^(-3) m = 8.75 mm` |
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