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In Young's double slit experiment, carried out with light of wavelength lambda= 5000 Å the distance between the slits is 0.2 mm and the screen is at 200 cm from the slits. The central maximum is at x = 0. The third maximum (taking the central maximum as zeroth maximum) will be at x equal to ...... |
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Answer» `1.67 cm` `=3xx5000xx10^(-10)xx(2)/(0.2xx10^(-3))` `=1.5xx10^(-2)m=1.5 cm` |
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