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In young's double slit experiment distance between the slits is 0.5 mm. When the screen is kept at a distance of 100 cm from the slits, the distance of ninth bright fring from the centre of the fringe system is 8.835 mm. Find the wavelength of light used. |
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Answer» Solution :GIVEN : `x_(N) = 8.85xx10^(-3)` d = 0.5 MM= `0.5xx10^(-3)` m, D=1m , n =9 Distance of `n^(th)` bright fringe is given by `x_(n) =(nlambdaD)/(d)` `lambda=(x_(n)d)/(nD)=(8.835xx10^(-3)xx0.5xx10^(-3))/(9xx1) = (4.4175)/(9) xx10^(-6)m = 4908 Å` |
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