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In young' s double slit experiment, for the light of wavelength lambda_(1) fringe y_(1) and for the light of wavelength lambda_(2) fringe width is y_(2) . If the whole arrangement is dipped into a liquid of refractive index muit is founded that for the wavelength lambda_(1)fringe width becomes y_(3) . Now the correct relation isFour light waves are represented by (i) y= a_(1) "sin" omega t""(ii) y= a_(2) "sin" ( omegat+e)(iii) y=a_(1) "sin" 2 (omegat) "" (iv) y= a_(2) "sin" 2 (omega t +e) |
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Answer» `y_(2)=y_(1)(lambda_(1))/(lambda_(2))` |
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