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In Young.s double slit experiment how many maximas can be obtained on a screen (including the central maximum) on both sides of the central fringe it lambda= 2000A^(0)" and "d= 7000A^(0). |
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Answer» Solution :For maximum intensity on the screen `d sin THETA = n LAMBDA (" or ") sin theta = (n lambda)/(d)= ((n)(2000))/((7000))= (n)/(3.5)` maximum value of `sin theta =1` `therefore n = -3, -2, -1, 0, 1, 2, 3` `therefore 7` maximas. |
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