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In Young's double slit experiment, if th distance between two slits is double of the wavelength of light used. Prove that maximum 5 bright fringes will be obtained on the screen. |
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Answer» Solution :CONDITION for bright fringe, `dsintheta=nlamda` where n=0,1 2, 3, …….. but `d=2lamda` is given. `:.2lamdasintheta=nlamda` `:.sintheta=(n)/(2)` but `sinthetale1` [RANGE of sine function] `:.(n)/(2)le1` `:.nle2` Thus, for `nle2` on SCREEN we have, (i) One central maximum for n = 0 (ii) Two first order maximum for n = 1. Two second order maximum for n = 2. `:.` We have TOTAL five bright FRINGES. |
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