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In Young's double slit experiment, the intensity at a point P on the screen is half the maximum intensity in the interference pattern. If the wavelength of light used is lambda and d is the distance between the slits, the angular separation between point P and the centre of the screen is ...... |
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Answer» `sin^(-1)((lambda)/(d))` `(I_(0))/(2)=I_(0) cos^(2){(2pi)/(lambda)XX(d sin THETA)/(2)}` `(1)/(2)=cos^(2){(PI d sin theta)/(lambda)}` `:.(1)/(sqrt(2))= cos {(pi d sin theta)/(lambda)}` `:.(pi)/(4)=(pi d sin theta)/(lambda)` `:. (lambda)/(4)= d sin theta :. theta sin^(-1)((lambda)/(4d))` |
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