Saved Bookmarks
| 1. |
In Young's double slit experiment two coherent sources of intensity ratio of 64 :1, produce interference fringes. Calculate the ratio of maximum and minimum intensities. Data : I_(1) : I_(2) :: 64 : 1, (I_(max))/(I_(min))=? |
|
Answer» Solution :`(I_(1))/(I_(2))=(a_(1)^(2))/(a_(2)^(2))=(64)/(1)` `:.(a_(1))/(a_(2))=(8)/(1)` or `a_(1)=8a_(2)` `(I_(MAX))/(I_(MIN))=((a_(1)+a_(2))^(2))/((a_(1)-a_(2))^(2))=((8a_(2)+a_(2))^(2))/((8a_(2)-a_(2))^(2))` `=((9a_(2))^(2))/((7a_(2))^(2))=(81)/(49)` `:.I_(max) : I_(min) : : 81 : 49` |
|