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In Young's double slit experiment using monochromatic light of wavelength lamda, the intensity of light at a point on the screen where path difference is lamda is K units. What is the intensity oflight at a point where path difference is(lamda)/3? |
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Answer» Solution :Inteference of waves from the two slits gives, Intensity`I=I_(1)+I_(2)+2sqrt(I_(1)I_(2)). cos phi` Phase difference `phi=(2pi)/(lamda)xx` PATH difference `=(2pi)/(lamda)xx lamda =2pi =0^(@)` `:.` Intensity `I=I+I+2sqrt(I.I) . cos 0^(@)=I+I+3I=4I=K` units (GIVEN) For path difference `(lamda)/3, phi=(2pi)/(lamda)xx(lamda)/3=(2pi)/3=120^(@)` `:.` Intensity`I.=I+I+2sqrt(I.I). cos 120=I+I+2I(1/(-2))=I=I/4` (Unit) |
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