In Young's experiement the width of the fringes obtained with light of wavelength 6000Å is 2mm. Calculate the fringe width if the entire apparatus is immersed in a liquid of refractive index 1.33. Data : lambda=6000Å=6xx10^(-7)m, beta=2mm=2xx10^(-3)m mu=1.33, beta=?

In Young's experiement the width of the fringes obtained with light of

1.	In Young's experiement the width of the fringes obtained with light of wavelength 6000Å is 2mm. Calculate the fringe width if the entire apparatus is immersed in a liquid of refractive index 1.33. Data : lambda=6000Å=6xx10^(-7)m, beta=2mm=2xx10^(-3)m mu=1.33, beta=?
Answer» SOLUTION :`beta=(Dlambda.)/(d)=(lambdaD)/(MUD)=(beta)/(MU)` `[:.mu=(lambda)/(lambda.)]` `:.beta.=(2XX10^(-3))/(1.33)=1.5xx10^(-3)m` (or) `1.5mm`.

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In Young's experiement the width of the fringes obtained with light of wavelength 6000Å is 2mm. Calculate the fringe width if the entire apparatus is immersed in a liquid of refractive index 1.33. Data : lambda=6000Å=6xx10^(-7)m, beta=2mm=2xx10^(-3)m mu=1.33, beta=?

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