1.

In Young's experiment, dark fringe of 5th order is obtained at point P on the screen so path difference at point P on the screen will be ......

Answer»

`(10 lambda)/(2)`
`(11lambda)/(2)`
`(9lambda)/(2)`
`(12lambda)/(2)`

Solution :For dark fringe,
Path DIFFERENCE `=(2n-1)(lambda)/(2)=(9lambda)/(2)[ :.n=5]`


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