1.

In Young's experiment distance between 5^(th) dark fringe and 3rd bright fringe is x_(5 )-x_(3)=......x

Answer»

2
3
`(2)/(3)`
`(3)/(2)`

Solution :For `5^(th)` DARK fringe,
`x_(5)=(9 lambdaD)/(2D) ""...(1)`
For `3^(rd)`bright fringe,
`x_(3)=(3lambdaD)/(d) ""...(2)`
`:.x_(3)-x_(3)=(9 lambdaD)/(2d)-(3lambdaD)/(d)`
`=(3lambdaD)/(2d)=(3)/(2) beta`


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