Saved Bookmarks
| 1. |
In Young's experiment ratio of maximum and minimum intensities of fringes is 9: 1. Ratio of amplitude of superposing waves = ..... |
|
Answer» Solution :`(I_(max))/(I_(min))= :.(9)/(1)=((E_(1)+E_(2))/(E_(1)-E_(2)))^(2)` `:. (E_(1)+E_(2))/(E_(1)-E_(2))=(3)/(1) [ :.` Taking SQUARE ROOT] Now, Taking componendo- dividendo, `(2E_(1))/(2E_(2))=(3+1)/(3-1) :. (E_(1))/(E_(2))=(2)/(1) =2:1` |
|