1.

In Young's experiment the distance between the slits is reduced to half and the distance between the slit and screen is doubled then the fringe width

Answer»

will not change
will BECOME half
will be doubled
will become FOUR times

Solution :As PER relation `beta=(lamdaD)/(d),beta.=(lamda(2D))/((d//2))=(4lamdaD)/(d)=4beta`


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