1.

In Zeigler-Natta polymerisation of ethylene, the active species is

Answer»

`AlCl_(3)`
`Et_(3)Al`
`CH_(2)CH_(2)`
`TL^(3+)`

SOLUTION :`(C_(2)H_(5))_(3)Al + TiCl_(4) rarr Active species`
`Ti_(3+)` has active SITE VACANT and thus acclmmodate one alkyl group `(as(C_(2)H_(5))_(3)Al reduces TiCl_(4) to TiCl_(3))` .


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