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Ina `0.25` litre dissociation of 4 moles of NO takes place. If its degree of dissociation is `10%`. The value of `K_(p)` for reaction `2NO hArrN_(2) + O_(2)` is:A. `(1)/((18)^(2))`B. `(1)/((8)^(2))`C. `(1)/(16)`D. `(1)/(32)` |
Answer» Correct Answer - A `{:(,2NO,hArr,N_(2),+,O_(2),alpha=10%),(t=0,4-.4,,.2,,.2,),(,3.6,,0.2,,0.2,):}` `Deltan=0`, `thereforeK_(p)=K_(c), K_(c)=((.2//V)^(2))/((3.6//V)^(2))=(4)/(36xx36)` |
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