1.

Ina certain town, 40% of the people have brown hair, 25% have browneyes, and 15% have both brown hair and brown eyes. If a person selected atrandom from the town has brown hair, the probability that he also has browneyes is`1//5`b. `3//8`c. `1//3`d. `2//3`A. `1//5`B. `3//8`C. `1//3`D. `2//3`

Answer» Correct Answer - B
We have, `P(A)=40/100,P(B)=25/100and P(AnnB)=15/100`
So, `P((B)/(A))=(P(AnnB))/(P(A))=(15//100)/(40//100)=3/8`


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