1.

Ina chemical equilibrium A+B hArrC+D, when one mole each ofhte two reactant are mixed, 0.6 male each of the products are formed. The equilibrium constant calculated is

Answer»

1
`0.36`
`2.25`
`4//9`

SOLUTION :`A+BhArrC+D`
initial `1" "1""0" "0`
REMAINING at EQULIBRIUM `0.4" "0.4""0.6" "0.6`
`K=([C][D])/([A][B])=(0.6xx0.6)/(0.4xx0.4)=36/16=2.25.`


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