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Initial voltage and input power of a transformer of effieciency `80%` are 100 V and 4 kW, respectively. IF the voltage of the secondary coil is 200 V, determine the currents flowing through the primary and the second ary coils? |
Answer» Power of the primary coil i.e., input power, `P_p=V_pI_p` or,`I_p=P_p/V_p=(4times1000)/100=40 A` Power of the secondary coil , `P_s=P_ptimes80/100`, Again, `P_s=V_sI_s` So, `I_s=P_s/V_s=80/100timesP_p/V_s=80/100times(4times1000)/200=16 A`. |
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