Initial volume of H_(2) gas saturated with water vapour is confined under a piston in a container is 10 litres as shown in the given figure. the container also contains some liquid water. The total pressure over liquid water is 80cm of Hg. If now the piston is removed such that volume of container is doubled, then final total pressure over liqid water in the container is P. The vapour pressure of water is 20cm of Hg and volume of liquid is negligible. Calculate P//10.........

Initial volume of H_(2) gas saturated with water vapour is confined un

1.	Initial volume of H_(2) gas saturated with water vapour is confined under a piston in a container is 10 litres as shown in the given figure. the container also contains some liquid water. The total pressure over liquid water is 80cm of Hg. If now the piston is removed such that volume of container is doubled, then final total pressure over liqid water in the container is P. The vapour pressure of water is 20cm of Hg and volume of liquid is negligible. Calculate P//10.........
Answer» Solution :`P_(1)V_(1)=P_(2)V_(2)` `P_(2)=` Pressure of `H_(2)` gas `=(60xx10)/20` `P_(2)=30cm` of `Hg` Final total pressure over liquid water `(P)=30+20=50 cm` of `Hg` `P/10=50/10=5`