Saved Bookmarks
| 1. |
Initially switch S is opened and energy stored between the plates of capacitor is E. Now the switch S is closed. Work done by battery after the switch S is closed is W. Find (2E)/W. |
|
Answer» `Q_(f)-Q_(i)=(2CV)/3-(CV)/2=(CV)/6` `E/W=(CV^(2)//4)/(CV^(2)//5)=3/2 implies(2E)/W=3` |
|