1.

Initially, the root mean square ( rms) velocity of N_(2) molecules at certain temperature is u. If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the rms velocity will be:

Answer»

2u
14u
4u
u/2

Solution :`rms(N_(2))=SQRT((3RT)/28)`
After dissociation, u. = `sqrt((3Rxx2T)/14)`
`u/(u.)=sqrt(1/4),u/(u.)=1/2,u.=2u`


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