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Initially the switch 'S' is open for a ling time. Now the switch 'S' is closed at t=0(R_(1)=2Omega, R_(2)=2Omega, C_(1)=1F and C_(2)=1F) Then |
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Answer» The current through the WIRE `AB` at `t=2` sec is `1//2e` ampere  When the switch is closed then at `t=0` the distribution of the charge is shown in the figure.  By applying Kirchooff's Law `I_(1)^(')=((1-q))/2` `int_(1//2)^(q) (dq)/(1-q)=int_(0)^(1) (dt)/2` `q=(1-1/2e^(-t//2))` `I_(1)^(')=(dq)/(dt)=1/4 e^(-t//2)` |
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