Instantaneous values of current and e.m.f in an AC circuit are `I=I//sqrt(2)sin 314` tamp and `E=sqrt(2)sin(314t-pi//6)V` respectively. The phase difference between `E` and `I` will beA. `- (pi)/(6)` radB. `- (pi)/(3)`C. `(pi)/(6)`D. `(pi)/(3)` rad

Instantaneous values of current and e.m.f in an AC circuit are `I=I//s

1.	Instantaneous values of current and e.m.f in an AC circuit are `I=I//sqrt(2)sin 314` tamp and `E=sqrt(2)sin(314t-pi//6)V` respectively. The phase difference between `E` and `I` will beA. `- (pi)/(6)` radB. `- (pi)/(3)`C. `(pi)/(6)`D. `(pi)/(3)` rad
Answer» Correct Answer - A `I = (1)/(sqrt(2)) sin 314 t` , `E = sqrt(2) sin (314 t - (pi)/(6))` with respect to current, the emf is lagging. So phase difference is `phi = - (pi)/(6)`

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Instantaneous values of current and e.m.f in an AC circuit are `I=I//sqrt(2)sin 314` tamp and `E=sqrt(2)sin(314t-pi//6)V` respectively. The phase difference between `E` and `I` will beA. `- (pi)/(6)` radB. `- (pi)/(3)`C. `(pi)/(6)`D. `(pi)/(3)` rad

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