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`int(1)/(7+5 cos x)dx=`A. `(1)/(sqrt(6))tan^(-1)((1)/(sqrt(6))"tan" (x)/(2))+C`.B. `(1)/(sqrt(3))tan^(-1)((1)/(sqrt(3))"tan" (x)/(2))+C`C. `(1)/(4)tan^(-1)((x)/(2))+C`D. `(1)/(7)tan^(-1)("tan" (x)/(2))+C` |
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Answer» Correct Answer - a We have , `I= int(1)/(7+5 cos x)dx= int(1+tan ^(2)x//2)/(7(1+"tan"^(2)(x)/(2))+5(1- " tan" ^(2)(x)/(2)))dx` `rArr I= int ("sec"^(2)(x)/(2))/(12+2"tan"^(2)(x)/(2))dx=int((1)/(2)"sec"^(2)(x)/(2))/((sqrt(6))^(2)("tan"(x)/(2))^(2))dx` `rArr I= int(1)/((sqrt(6))^(2)+("tan"(x)/(2))^(2))d ("tan"(x)/(2))=(1)/(sqrt(6))tan^(-1)((1)/(sqrt(6))"tan"(x)/(2))+C` |
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