InterviewSolution
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InterviewSolution
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`int(1+sinx)/(1+cos x)dx` का मान ज्ञात कीजिए। |
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Answer» दिया है - `int((1+sin x))/((1+cosx))dt` ` = int(1)/(1+cosx)dt + int(sinx)/((1+cosx))dx` `= int(1)/(2cos^(2)(x//2))dx + int(2sin(x//2)cos(x//2))/(2cos^(2)(x//2))` ` = (1)/(2)intsec^(2)((x)/(2))dx + int tan((x)/(2))dx` यदि `t = x//2` व `dx = 2dt` `=intsec^(2) t dt + 2 int tan tdt ` ` = tan t - 2 log (cos t) + c` ` = tan((x)/(2)) - 2 log cos((x)/(2))+c` |
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