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`int cos mx cos nx dx` का मान ज्ञात कीजिए। |
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Answer» दिया है - ` int cos mx cos nx dx` यदि `m ne n` तब ` = (1)/(2)int[cos(m +n)x + cos(m -n)x]dx` ` = (1)/(2)intcos(m+n) xdx +(1)/(2)int cos (m-n)x dx` ` = (sin (m +n) x)/(2(m+n))+(sin(m-n)x)/(2(m-n))+c` अब यदि `m =n` तब `int cos mx cos nx dx = int cos^(2) nx dx ` ` = (1)/(2)int2cos^(2) nx dx` ` = (1)/(2)int dx + (1)/(2)int cos 2nx dx` ` = (x)/(2) +(sin 2nx)/(4n)+c` |
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