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`int cos mx cos nx dx` का मान ज्ञात कीजिए।

Answer» दिया है - ` int cos mx cos nx dx`
यदि `m ne n` तब
` = (1)/(2)int[cos(m +n)x + cos(m -n)x]dx`
` = (1)/(2)intcos(m+n) xdx +(1)/(2)int cos (m-n)x dx`
` = (sin (m +n) x)/(2(m+n))+(sin(m-n)x)/(2(m-n))+c`
अब यदि `m =n` तब
`int cos mx cos nx dx = int cos^(2) nx dx `
` = (1)/(2)int2cos^(2) nx dx`
` = (1)/(2)int dx + (1)/(2)int cos 2nx dx`
` = (x)/(2) +(sin 2nx)/(4n)+c`


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