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`int_(5)^(10) ""(1)/((x-1)(x-2))dx` is equal toA. `log""(27)/(32)`B. `log""(32)/(27)`C. `log""(8)/(9)`D. `log""(3)/(4)` |
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Answer» Correct Answer - B Let `I=int_(5)^(10)""(1)/((x-1)(x-2)) dx ` `=int_(5)^(10)[(-1)/(x-1)+(1)/(x-2)] dx ` `=[-log (x-1)+ log (x-2)]_(5)^(10)` `=- log 9 +log 8 + log 4- log 3` `= -2 log 3 + 3 log 2 + 2 log 2 - log 3 ` ` =- 3 log 3 + 5 log 2 ` `=- log 27 + log 32` `= log""(32)/(27)` |
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