InterviewSolution
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InterviewSolution
| 1. |
`int(d theta)/(sin(theta - alpha)sin(theta-beta))`का मान ज्ञात कीजिए। |
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Answer» माना `I = int(d theta)/(sin(theta - alpha)sin(theta -beta))` ` int(sin(alpha - beta)d theta)/(sin(alpha-beta)sin(theta-alpha)sin(theta-beta))` ` = (1)/(sin(alpha - beta))int(sin[(theta - beta)- (theta - alpha)])/(sin(theta-alpha)sin(theta-beta))d theta` ` = (1)/(sin(alpha-beta))` ` int(sin(theta-beta) cos(theta-beta)-sin(theta-beta)cos(theta-beta))/(sin(theta -alpha)sin(theta-beta))` `=(1)/(sin(alpha -beta))int{(cos(theta - alpha))/(sin(theta-alpha))-(cos (theta - beta))/(sin(theta-beta))} d theta` `=(1)/(sin(alpha-beta))[int(cos (theta -alpha))/(sin(theta-alpha))d theta-int(cos(theta - beta))/(sin(theta-beta))d theta]` `=(1)/(sin(alpha-beta))[log sin(theta-alpha) - log sin (theta - beta)]` ` = (1)/(sin(alpha-beta))log[(sin(theta-alpha))/(sin(theta-beta))]" "(because log M - log N = log.(M)/(N))` |
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