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`int sec^(6//5)x coses ^(4//5) x dx` का माना ज्ञात कीजिये। |
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Answer» माना `I = int sec^(6//5)x cosec ^(4//5) x dx` `= int(sec^(2)x//dx)/(sin^(4//5)x) xx (sec^(4//5) x)/(sec^(4//5x)) dx` अश और हर को `sec ^(4//5)` x से गुणा करने पर `int (sec^(2)x dx)/(tan^(4//5)x)` माना `tan x = t rArr sec^(2)xdx = dt` `therefore" "I = int (dt)/(t^(4//5)) = int t^(4//5)dt = 5t^(1//5) 5(tan x)^(1//5)` |
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