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`int[sin(logx)+cos(logx)]dx`A. ` x cos( log x )+c`B. `cos ( log x )+c`C. `x sin ( logx)+c `D. `sin ( log x)+c `

Answer» Correct Answer - C
`int[ sin (log x)+ cos ( log x )] dx `
`= int (d)/(dx){x sin ( log x) } dx `
`= x sin ( log x )+c `


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