`int(sin(tan^(-1)x))/(1+x^(2))dx = - cos tan^(-1)x+c` सिद्ध कीजिये -

`int(sin(tan^(-1)x))/(1+x^(2))dx = - cos tan^(-1)x+c` सिद्ध

1.	`int(sin(tan^(-1)x))/(1+x^(2))dx = - cos tan^(-1)x+c` सिद्ध कीजिये -
Answer» बाया पक्ष`= int(sin(tan^(-1)x))/(1+x^(2))dx` माना `tan^(-1) x = t` `rArr(1)/(1+x^(2))dx = dt` `therefore int(sin(tan^(-1)x))/(1+x^(2))dx = intsin t dt = - cos t + c` `= - cos (tan^(-1)x)+c=` दाया पक्ष